The mass of carbon present in 91.00 g of propane is 74.29 g.
Since we have 91.00 g of propane C₃H₈, the ratio of carbon to hydrogen is 3 : 8. So, for every mole of propane, we have 3 moles of carbon to 8 moles of hydrogen.
To find the mass of carbon, we first need to find the number of moles of carbon present in 91.00 g of propane. To do that, we find the number of moles of propane present in 91.00 g.
Since there are 36.03 g of C for each 8.07 g, the molar mass of propane C₃H₈ = 36.03 g + 8.07 g = 44.1 g
The number of moles n of propane present = mass of propane/molar mass of propane = 91.00 g/44.1 g = 2.064 mol
Now, since for every mole of C₃H₈, there are 3 moles of carbon, C. So, for 2.064 mol of C₃H₈, there will be x moles of C.
So, x = 2.064 × 3 = 6.19 mol
Since the molar mass of carbon = 12.01 g/mol, and
number of moles of carbon = mass of carbon/molar mass of carbon
mass of carbon = number of moles of carbon × molar mass of carbon
= 6.19 mol × 12.01 g/mol
= 74.29 g
So, the mass of carbon present in 91.00 g of propane is 74.29 g.
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