Respuesta :

Let's write the equation

[tex]\\ \sf\longmapsto {NaOH\atop ?}+{HCl\atop 73g}\longrightarrow {NaCl\atop 117g}+{H_2O\atop 36g}[/tex]

According to law of conservation of mass .

  • Mass of products=Mass of reactants

Let required value be x

[tex]\\ \sf\longmapsto x+73=117+36[/tex]

[tex]\\ \sf\longmapsto x+73=153[/tex]

[tex]\\ \sf\longmapsto x=153-73[/tex]

[tex]\\ \sf\longmapsto x=80g[/tex]

Sᴘᴀᴄᴇ7

Answer:

x=80g

Explanation:

Equation:

[tex]\sf NaOH + HCL = NaCl + H _{2} O.[/tex]

? 73g 117g 36g

Let the required value be x.

x + 73 = 117 + 36

x + 73 = 153

x = 153 - 73

x = 80g.

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Note:Mass of products = mass of reactants.