The acceleration of the car is 0.5 meters per seconds square.
Given the following data:
Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.
To find the acceleration of the car, we would use the third equation of motion;
Mathematically, the third equation of motion is given by the formula;
[tex]V^2 = U^2 - 2aS\\\\0 = 30^2 - 2a(900)\\\\0 = 900 - 1800a\\\\1800a = 900\\\\a = \frac{900}{1800}[/tex]
Acceleration, a = 0.5 [tex]m/s^2[/tex]
Therefore, the acceleration of the car is 0.5 meters per seconds square.
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