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The acceleration of the car is 0.5 meters per seconds square.

Given the following data:

  • Initial velocity, U = 30 m/s
  • Distance, S = 900 meters

Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.

To find the acceleration of the car, we would use the third equation of motion;

Mathematically, the third equation of motion is given by the formula;

[tex]V^2 = U^2 - 2aS\\\\0 = 30^2 - 2a(900)\\\\0 = 900 - 1800a\\\\1800a = 900\\\\a = \frac{900}{1800}[/tex]

Acceleration, a = 0.5 [tex]m/s^2[/tex]

Therefore, the acceleration of the car is 0.5 meters per seconds square.

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