The segment bisector of [tex]\overline{RS}[/tex] is [tex]\overrightarrow{MA}[/tex]
The value of [tex]\overline{RS} = 18[/tex]
Complete Question:
Identify the segment bisector of RS. Then find RS:
- Also, see attachment for the image being referred to.
Recall:
A segment bisector is a line or part of a line that divides a segment into two equal segments or parts.
Thus:
From the image in number 4, we have line RS that is divided by [tex]\overrightarrow{MA}[/tex] into two equal segments, namely:
RM and MS
The segment bisector of [tex]\overline{RS}[/tex] is therefore [tex]\overrightarrow{MA}[/tex].
Thus:
[tex]RM = MS = 9[/tex] (equal segments)
[tex]RM + MS = RS[/tex] (segment addition postulate)
Substitute:
[tex]9 + 9 = \overline{RS}\\18 = \overline{RS}\\\overline{RS} = 18[/tex]
Therefore:
The segment bisector of [tex]\overline{RS}[/tex] is [tex]\overrightarrow{MA}[/tex]
[tex]\overline{RS} = 18[/tex]
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