The question is an illustration of mean or averages.
If he pours equal amount in the glasses, [tex]8\frac{3}{4} oz[/tex] would be in each glass
I've added as an attachment, the missing line plot.
The data on the line plot can be represented as follows:
[tex]\left[\begin{array}{cccccccc}x&7&7\frac 12&8&8\frac12&9&9\frac 12 & 10 \\f&0&0&2&1&4&1&0\end{array}\right][/tex]
Where:
[tex]x \to[/tex] the glasses
[tex]f \to[/tex] number of ounces
Glasses with no x on the line plot have a frequency of 0.
If he pours an equal amount of ounces in each glass, the amount in each glass is the mean.
The mean is then calculated as:
[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]
So, we have:
[tex]\bar x = \frac{0 \times 7 + 7\frac 12 \times 0 + 8 \times 2 + 8\frac 12 \times 1 + 9 \times 4 + 9\frac 12 \times 1 + 10 \times 1}{0 + 0 + 2+1+4+1+0}[/tex]
[tex]\bar x = \frac{0 + 0 + 16 + 8\frac 12 + 36 + 9\frac 12+ 10}{8}[/tex]
[tex]\bar x = \frac{70}{8}[/tex]
Simplify
[tex]\bar x = 8\frac{3}{4}[/tex]
Hence, if he pours equal amount in the glasses, [tex]8\frac{3}{4} oz[/tex] would be in each glass
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