The coordinate of point A that divides the line BC into ratio of 2 to 1 is (0, -1)
The midpoint formula to get the coordinate of point A is expressed as:
[tex]A(X,Y) = (\frac{ax_1+bx_2}{a+b}, \frac{ay_1+by_2}{a+b})[/tex]
Given the coordinates B(-3, -2) and C(6,1) divided into a ratio 2 to 1, the coordinate of point A on BC will be;
[tex]A(X,Y) = (\frac{2(-3)+1(6)}{2+1}, \frac{2(-2)+1(1)}{2+1})\\A(X,Y) = (\frac{-6+6}{3}, \frac{-4+1}{3})\\A(X,Y) = (\frac{0}{3}, \frac{-3}{3})\\A(X, Y) = (0, -1)[/tex]
Hence the coordinate of point A that divides the line BC into ratio of 2 to 1 is (0, -1)
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