We have that The moles of air are in the cylinder and the volume would this air occupy at 1.0 atm and room Temperature is
From the question we are told
Generally the equation for the Volume of Cylinder is mathematically given as
[tex]V=\pi r^2l\\\\V=\pi *{\frac{20}{2*100}}*1\\\\V=31.4L[/tex]
Therefore
The equation for the ideal gas is mathematically given as
[tex]PV=nRT\\\\n=\frac{PV}{RT}\\\\n=\frac{180*31.4}{0.082*300}\\\\n=229.756[/tex]
Generally the equation for the ideal gas is mathematically given as
[tex]PV=nRTWhere\\\\V=\frac{nRT}{P}\\\\V=229.756*0.082*300\\\\V=5651.997L[/tex]
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