The average velocity is a vector magnitude we can find that its value is:
v = 3.63 10-2 m/ s
with a direction 74 to the South of the East
Giving parameters
To find
The velocity in a vector quantity that is defined as the change in displacement between time during the interval
v = [tex]\frac{\Delta s}{\Delta t}[/tex]
Where v is the veloicity, Δs and Δt are de positivo and time variation
To find the displacement let's use the Pythagoras' theorem
d = [tex]\sqrt{(\Delta x)^2 + (\Delta y)^2}[/tex]
We assume that the displacements to the right (east) and upwards (north) are positive
Δx = 17-14
Δx = 3 m
Δy = 12 -22.5
Δy = -10.5 m
The distance traveled is
d = [tex]\sqrt{3^2 + 10.5^2 }[/tex]
d = 10.9 m
The speed module is
v = 10.9 / 300
v = 3.63 10⁻² m / s
The direction of this velocity is given by the angle of this displacement can be found using trigonometry
tan θ = [tex]\frac{\Delta y}{\Delta x}[/tex]
θ = tan⁻¹ [tex]\frac{\Delta y}{\Delta x}[/tex]
θ = tan⁻¹ [tex]\frac{-10.5}{3}[/tex]
θ = -74º
This angle is measured clockwise from the positive side of the x-axis.
Orea way to give this angle is
θ = 74 south of East
In conclusion the average speed is
v = 3.63 10-2 m / s
With a direction 74 to the South of the East
Learn more about average velocity here:
https://brainly.com/question/12322912
