We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).
[tex]0.500 L \times \frac{0.360mol}{L} = 0.180 mol[/tex]
Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).
[tex]0.180 mol \times \frac{110.98g}{mol} = 20.0 g[/tex]
To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
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