Respuesta :

Estimation simply means an approximated value.

  • Estimation gives the range of the first digit of the quotient
  • Multiplication is the inverse of division.
  • [tex]663 \div 3 = 112[/tex].
  • [tex]487 \div 8 = 60\ R\ 7[/tex].
  • [tex]1641 \div 4 = 410\ R\ 1[/tex].
  • [tex]2765 \div 9 = 307\ R\ 2[/tex]

Estimation in whole-number quotient

A whole number quotient is represented as:

[tex]\frac ab = c[/tex]

Where:

[tex]a,b, c \to[/tex] whole numbers

When the numbers are estimated, one would get the idea of the range of values the first digit can assume.

Take for instance:

[tex]\frac{117}{3}[/tex]

117 can be estimated as 120. So, we have:

[tex]\frac{117}{3} \approx \frac{120}{3}[/tex]

120 divided by 3 is 40.

The first digit of 120 divided by 3 is 4.

So, estimating 117 as 120 makes us know that the first digit of 117 divided by 3 would either be 4 or less.

(b) Multiplication in division problem

Multiplication and division are both inverse operations.

So, multiplication is used to check the dividend of the division problem.

Take for instance:

[tex]\frac{117}{3} = 39[/tex]

If the above division is correct, then 39 multiplied by 3 must be 117 i.e.

[tex]39 \times 3 = 117[/tex]

[tex](c)\ 663 \div 3[/tex]

Start by dividing the first 6 by 3

[tex]663 \div 3 \to 1[/tex]

Divide the next 6 by 3

[tex]663 \div 3 \to 11[/tex]

Divide the last 3 by 3

[tex]663 \div 3 = 112[/tex]

[tex](d)\ 487 \div 8[/tex]

Divide 4 by 8

[tex]487 \div 8 \to 0[/tex]

Since the result is 0 and 4 is not the last digit, we then try 48.

Divide 48 by 8

[tex]487 \div 8 \to 06[/tex]

Divide 7 by 8.

[tex]487 \div 8 \to 060[/tex]

7 is less than 8; this means that 8 cannot divide 7.

So, we write 7 as the remainder

[tex]487 \div 8 = 060\ R\ 7[/tex]

Remove the leading 0

[tex]487 \div 8 = 60 R 7[/tex]

[tex](e)\ 1641 \div 4[/tex]

Divide 1 by 4

[tex]1641 \div 4 \to 0[/tex]

Divide 16 by 4

[tex]1641 \div 4 \to 04[/tex]

Divide 4 by 4

[tex]1641 \div 4 \to 041[/tex]

Divide 1 by 4

[tex]1641 \div 4 \to0410[/tex]

1 is less than 4; this means that 8 cannot divide 1.

So, we write 1 as the remainder

[tex]1641 \div 4 \to 0410\ R\ 1[/tex]

Remove the leading 0

[tex]1641 \div 4 = 410\ R\ 1[/tex]

[tex](f)\ 2765 \div 9[/tex]

Divide 2 by 9

[tex]2765 \div 9 \to 0[/tex]

Divide 27 by 9

[tex]2765 \div 9 \to 03[/tex]

Divide 6 by 9

[tex]2765 \div 9 \to 030[/tex]

6 is less than 9; this means that 9 cannot divide 6.

So, the next division will be 65 by 9

[tex]2765 \div 9 \to 0307[/tex]

9 divides 63 in 7 places, with a remainder of 2.

So, we have:

[tex]2765 \div 9 = 0307 R 2[/tex]

Remove the leading 0

[tex]2765 \div 9 = 307 R 2[/tex]

Read more about division and multiplications at:

https://brainly.com/question/19928607