A vector quantity has both magnitude and direction, and therefore, can be resolved into components
The magnitude of the vector, G is approximately 5 units
The value of the magnitude of the vector is correct for the following reason:
The given parameters are;
The direction in which the vector, G, is pointed, θ = 36.9° clockwise rotation from the positive y-axis
The x-component of the vector = 3
Required:
To find the magnitude of the vector
Solution:
Let |G|, represent the magnitude of the vector
Given that the angle, is measured from the y-axis, we have;
|G| × sin(θ) = The x-component of the vector
Therefore;
|G| × sin(36.9°) = 3
[tex]|G| = \dfrac{3}{sin(36.9^{\circ})} \approx 4.9965 \approx 5[/tex]
The magnitude of the vector, G ≈ 5
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