The two different ions present in the compound magnesium bromide are [tex]Mg^{2+}[/tex]and [tex]Br^-[/tex].
Given:
The compound [tex]MgBr_2[/tex]
To find:
The two different ions in the given compound.
Solution:
The given compound is magnesium bromide, [tex]MgBr_2[/tex] .
Magnesium bromide is made up of magnesium ions and bromide ions.
Magnesium ion +2 bromide ions → Magnesium bromide
[tex]Mg^{2+}+2Br^-\rightarrow MgBr_2[/tex]
The ion with a positive charge (cation) = Magnesium ion = [tex]Mg^{2+}[/tex]
The ion with a negative charge (anion) = Bromide ion = [tex]Br^-[/tex]
The two different ions present in the compound magnesium bromide are [tex]Mg^{2+}[/tex]and [tex]Br^-[/tex].
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