We need to find the inequality that represents how the $55 I have can be spent in the fair.
The required inequality is [tex]12+1.75x\leq55[/tex], and the possible number of rides is [tex]24[/tex].
Admission cost = $12
Cost of each ride = $1.75
Let [tex]x[/tex] be the number of rides taken.
Total cash = $55
So, the inequality will be [tex]12+1.75x\leq55[/tex]
Solving the inequality
[tex]1.75x\leq55-12\\\Rightarrow x\leq\dfrac{55-12}{1.75}\\\Rightarrow x\leq 24.57[/tex]
So, the maximum number of rides taken can be [tex]24[/tex].
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