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Write the nuclear equation for each of the following reactions. Refer to a periodic table.
a. the alpha decay of Radium-226
b. the beta decay of Chlorine-39

Respuesta :

Answer:

a. 226/88Ra --> 222/86Rn + 4/2He

Explanation:

Alpha decay you lose four from the mass number and two from the Atomic number. Giving you 222 mass and 86 atomic. Radon has 222 mass and 86 atomic 222/86Rn + the four from the mass we took and the two from the atomic we took. What element has 4 mass and 2 atomic. Helium 4/2He  

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