The speed that the person needs to leave the ground will be 4.32m/s
From the question given,
Height = 95cm
Since the person leave the ground v = 0m/s
acceleration due to gravity g = 9.8m/s²
Using the equation of motion
v² = u² + 2as
a = -g (upward motion)
s = h (distance changes to height)
The equation will become:
0² = u² - 2gh
0² = u² - 2(9.8)(0.95)
u² = 18.62
u = √18.62
u = 4.32
Hence the speed that the person needs to leave the ground will be 4.32m/s
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