The sprinter’s average acceleration is 1.98 m/s²
The given parameters;
Convert the velocity of the sprinter to m/s;
[tex]initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\[/tex]
The time of motion is seconds;
[tex]t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s[/tex]
The sprinter’s average acceleration is calculated as follows;
[tex]a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2[/tex]
Thus, the sprinter’s average acceleration is 1.98 m/s²
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