Respuesta :

Question:-

A man standing on a road has to hold his umbrella in 30° with the vertical to keep the rain away.He throws the umbrella and starts running at 10km/h.He finds that raindrops are hitting his head vertically .Find the speed of rain w.r.t road.

Answer:-

Look at the attachment

[tex]\\ \sf\longmapsto tan\Theta=\dfrac{Perpendicular}{Base}[/tex]

[tex]\\ \sf\longmapsto tan30=\dfrac{V_{RAIN}}{10}[/tex]

[tex]\\ \sf\longmapsto \sqrt{3}=\dfrac{V_{RAIN}}{10}[/tex]

[tex]\\ \sf\longmapsto V_{RAIN}=10\sqrt{3}km/s[/tex]

option C

Ver imagen Аноним

Answer:

• From trigonometric ratios:

[tex]{ \boxed{ \rm{ \tan( \theta) = \frac{opposite}{adjacent} }}} \\ [/tex]

• theta is 30°

• opposite speed is Vp

• adjacent speed is 10 km/h

[tex]{ \tt{ \tan(30 \degree) = \frac{v _{p} }{10} }} \\ \\ { \tt{v _{p} = 10 \tan(30 \degree) = 10 \times \sqrt{3} }} \\ \\ { \underline{ \underline{ \tt{ \: \: v _{p} = 10 \sqrt{ 3} \: km }}}}[/tex]

Otras preguntas