GREG PUTS MONEY IN HIS DAUGHTERS PIGGY BANK EVERY DAY HE PUTS IN $0.75 BUT ON SUNDAYS HE PUTS IN $5.75 IF HE CONTINUES THUS FOR A YEAR HOW MUCH WILL HIS DAUGHTER HAVE IN HER PIGGY BANK ASSUME THERE ARR 52 WEEKS IN A YEAR.

Respuesta :

Greg's daughter will have $533 in her piggy bank in a year

The money in the piggy bank would increase everyday by the amount put in it. There are seven days in a week. If he puts $0.75 everyday apart from on Sundays when we puts $5.75, the amount that would be in the piggy bank in a week is the sum of the money deposited each day.

Total amount in a week = total amount deposited from Monday to Saturday + amount deposited on Sunday

  • Amount that Greg puts in 6 days : ($0.75 x 6) = $4.50
  • Amount deposited on Sunday = $5.75
  • Total amount =  $5.75 + $4.50 = $10.25

The total amount Greg's daughter would have in a year is a function of the number of weeks in year and the total amount saved in a week

Total amount in a year = number of weeks in year x the total amount saved in a week

  • Number of weeks in year = 52
  • The total amount saved in a week = $10.25

$10.25 x 52 = $533

In order to determine how much Greg's daughter would have in a year, first determine how much she would have in a week. Multiply this amount by the number of weeks in a year

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