The mean of a distribution is the sum of the data elements divided by the count of the dataset.
The mean of the distribution is 4
The complete table is given as
[tex]\left[\begin{array}{cc}People & Frequency &0 - 2 & 5 & 3 - 5 & 25 & 6 - 8 & 5\end{array}\right][/tex]
The complete question requires that, we calculate the mean of the dataset
First, we calculate the class midpoint
This is the average of the class interval
For interval 0 - 2,
[tex]x_1 = \frac{0 + 2}{2} = 1[/tex]
For interval 3 - 5,
[tex]x_2 = \frac{3 + 5}{2} = 4[/tex]
For interval 6 - 8
[tex]x_3 = \frac{6 + 8}{2} = 7[/tex]
So, the table becomes
[tex]\left[\begin{array}{ccc}People & x & Frequency &0 - 2 &1 & 5 & 3 - 5 & 4& 25 & 6 - 8& 7 & 5\end{array}\right][/tex]
The mean is then calculated as:
[tex]\bar x = \frac{\sum fx}{\sum f }[/tex]
This gives
[tex]\bar x = \frac{5 \times 1 + 25 \times 4 + 5 \times 7}{5 + 25 + 5}[/tex]
[tex]\bar x = \frac{140}{35}[/tex]
[tex]\bar x = 4[/tex]
Hence, the mean of the distribution is 4
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