Respuesta :
Acceleration, speed where the speed changes over time, in both direction and speed, and simple time definition to modify, or the timeframe to alter, and the further calculation can be defined as follows:
Given:
[tex]\bold{\text{initial velocity} \ (U)} =0 \\\\\bolf{ \text{Final velocity}\ V}= 130 \frac{cm}{s}\\\\\bold{ \text{Displacement}} = 140\ cm\\[/tex]
To find:
Calculate time that will take by marble to bottom of the ramp.
Solution:
Using formula:
[tex]\to \bold{V^2=U^2 + 2 \times acceleration \times Displacement}[/tex]
[tex]\to \bold{V=U+a \times Time}[/tex]
By the first formula we calculate the acceleration:
[tex]\to \bold{130^2 = 0 + 2 \times acceleration \times 140}\\\\[/tex]
[tex]\to \bold{130^2 = 2 \times acceleration \times 140}[/tex]
[tex]\to \bold{acceleration = \frac{130^2}{2\times 140}}[/tex]
[tex]\bold{= \frac{130\times 130}{2\times 140}}\\\\\bold{= \frac{130\times 13}{2\times 14}}\\\\\bold{= \frac{65\times 13}{14}}\\\\\bold{= \frac{ 845}{14}}\\\\\bold{= 60.35\ \frac{cm}{s^2}} \\\\[/tex]
After calculating the acceleration putting value into the second formula and calculate the time:
[tex]\to \bold{V=U + a \times Time}\\\\\to \bold{Time = \frac{V}{a}}\\\\[/tex]
[tex]\bold{=\frac{130}{60.35} }\\\\\bold{=\frac{130}{60.35} }\\\\= \bold{2.15\ second}[/tex]
Learn more:
brainly.com/question/3344685
