Suzette ran and biked for a total of 34 mi in 3.5 h. Her average running speed was 6 mph and her average biking speed was 12.5 mph.
Let x = total hours Suzette ran.
Let y = total hours Suzette biked.
Use substitution to solve for x and y. Show your work. Check your solution.
(a) How many hours did Suzette run?
(b) How many hours did she bike?

Respuesta :

Answer:

The speed of an object is the rate of distance traveled over time. Suzette ran for 1.5 hours, and she biked for 2 hours.

Given that: Speed is calculated as: Make Distance the subject Average running speed = 6 mph for x hours implies that: Average biking speed = 12.5 mph for y hours implies that: So, the total distance is: The total distance is 34 miles. So, we have: The total time is 3.5h. So, we have: Make x the subject Substitute in Collect like terms Divide both sides by 6.5 Recall that: Hence, Suzette ran for 1.5 hours, and she biked for 2 hours.'

x=3.5-y

x-3.5-2

x=1.5

fichoh

Using Substitution, we can conclude that Suzette ran for 1.5 hours and biked for 2 hours

We can create a system of equation as follows :

Total hours :

  • x + y = 3.5 - - - (1)

Time taken to cover her distance :

  • 6x + 12.5y = 34 - - - (2)

From (1) :

  • x = 3.5 - y - - - (3)

Substitute x = 3.5 - y in (2):

6(3.5 - y) + 12.5y = 34

21 - 6y + 12.5y = 34

21 + 6.5y = 34

6.5y = 34 - 21

6.5y = 13

y = 13 / 6.5

y = 2

From (3):

x = 3.5 - 2

x = 1.5

Hence, Suzette ran for 1.5 hours and biked for 2 hours

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