A 41 foot tall tree fell into a building . The total height of the building is 68 feet.
Given :
The height of the tree is 41 foot.
Tree is 9ft away from the building . The tree fell into a building and it makes a right angle triangle .
Let x be the distance between the ground and the top of tree after it fell into a building .
Apply Pythagorean theorem to find out x
[tex]c^2=a^2+b^2\\[/tex]
where c is the height of the tree that is 41ft
a is the base that is 9 ft
Substitute the values and solve for x
[tex]c^2=a^2+b^2\\41^2=9^2+x^2\\9^2+x^2-9^2=41^2-9^2\\x^2=1600\\Take \; square \; root \\x=\sqrt{1600}\\x=40[/tex]
The distance between the ground and the top of tree is 40 ft
[tex]h=40+28\\h=68 ft[/tex]
The total height of the building is 68 feet
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