dennisj1
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A 2000 kg car traveling at a speed of 34 m/s skids to a halt on wet concrete where μk = 0.40. How long are the skid marks?

Respuesta :

The skid marks are about 295m long

The formula for calculating the frictional force is expressed as;

[tex]F=\mu R[/tex]

Since the car is travelling at a speed, the expression becomes

[tex]\frac{mv^2}{r}=\mu R[/tex]

m is the mass = 2000kg

v is the velocity = 34m/s

r is  the distance taken to skid

μ is coefficient of friction = 0.4

R is the normal reaction = mg = 2000 (9.8)

R = 19600N

Substitute the given values to get "r"

[tex]\frac{2000(34)^2}{r}=0.4 \times 19600\\\frac{2312000}{r} = 7840\\r=\frac{2312000}{7840}\\r= 294.89m[/tex]

Hence the skid marks are about 295m long.

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