dennisj1
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A trampolinist flies straight up into the air, then back down onto the trampoline, where she comes instantaneously to rest when the trampoline is fully stretched. Rank in order, from largest to smallest, her apparent weight.

a. When she is instantaneously at rest.

b. Just before she leaves the trampoline.

c. When she is at the top of her flight.


(Wapp)c, (Wapp)b, (Wapp)c

Respuesta :

The apparent weight is given by the sum of the actual weight, and the force due to acceleration

Just before she leaves the trampoline > When she is instantaneously at rest > When she is at the top of her flight

The reasons the above order is correct are given as follows:

  • When she is instantaneously at rest, we have;

Acceleration, a = 0

Apparent weight,  [tex]W_a[/tex] = m × (g + 0) = m·g = W

[tex]W_a[/tex] =  W

  • Just before she leaves the trampoline;

Just before, the trampolinist leaves the trampoline, with an upward acceleration, a, the net acceleration is (g + a), and the apparent weight,  [tex]W_a[/tex], is therefore;

Apparent weight is, [tex]W_a[/tex] = m × (g + a)

  • When she is at the top of her flight:

When she is at the top of her flight, we have that apparent weight of the which is the force felt supporting her motion, is zero (0) (no force is moving her upwards and instantaneously, she is weightless (able to remain at a point in the air).

Therefore, at the top of her flight, [tex]W_a[/tex] = 0

Which gives in order from largest to smallest;

Just before she leaves the trampoline > When she is instantaneously at rest > When she is at the top of her flight

Learn more about apparent weight here:

https://brainly.com/question/14019684

https://brainly.com/question/16805000

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