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A car begins at rest and accelerates. Its distance in meters, C(t), can be determined as a function
of time in seconds, t, by the formula C^1(t) = 4t^2.

A second car, 150 meters ahead, is traveling at
a constant speed of 20 meters per second. Its distance, (C^2), in meters can be determined as
a function of time, t, in seconds by the formula C^2(t) = 20t+ 150. How long after the first car
accelerates will the cars be side by side?
Round to the nearest hundredth, if necessary.

Respuesta :

adioabiola

Here, we are required to determine how long after the first car accelerates will the cars be side by side.

The cars will be side by side at Time, t = 9.11seconds after the first car accelerates.

The position of each car is given by the function of its distance, i.e C1 and C2.

At the point when the cars are side by side;

C^1(t) must be equal to C^2(t).

Mathematically;

  • C^1(t) = C^2(t)

  • C^1(t) = C^2(t)i.e 4t² = 20t + 150

Therefore, we have;

  • 2t - 10t -75 = 0

By solving quadratically;

We have ; Time, t = 9.11 seconds. (to the nearest hundredth).

Read more:

https://brainly.com/question/18920363

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