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Suppose that there are 2 red balls, 2 blue ball, and 1 white balls in an urn. A ball is drawn and its color is noted. After the ball is drawn, it is set aside and is replaced with a blue ball. Another ball is then drawn from the urn. Find the probability the first ball drawn was red given that the second ball drawn was blue.

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francocanacari

The probability that the first ball drawn was red is 20%.

Supposing that there are 2 red balls, 2 blue ball, and 1 white balls in an urn, and that a ball is drawn and its color is noted, and that after the ball is drawn, it is set aside and is replaced with a blue ball, and that another ball is then drawn from the urn, to find the probability the first ball drawn was red given that the second ball drawn was blue, the following calculation must be performed:

  • 2 + 2 + 1 = 5
  • 2 red of 5 total
  • 2/5 = 0.2
  • 0.2 x 100 = 20

Therefore, the probability that the first ball drawn was red is 20%.

Learn more in https://brainly.com/question/16484393

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