Triangle ABC has vertices A(-3,0) B(0,6) C(4,6). Find the equations of the three altitudes of triangle ABC

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Answer:

  • altitude to A: x = -3
  • altitude to B: 7x +6y = 36
  • altitude to C: x +2y = 16

Step-by-step explanation:

The calculations are repetitive, so it can be useful to use a spreadsheet to do them.

Altitude to A

The altitude to point A will be the line perpendicular to BC through point A. A way to write that equation is ...

  (Cx -Bx)x + (Cy -By)y = (Cx -Bx)(Ax) + (Cy -By)(Ay)

  (4 -0)x + (6 -6)y = (4 -0)(-3) +(6 -6)(0)

  4x = -12

  x = -3 . . . . . . . simplify to standard form (divide by 4)

Performing similar calculations on the other points, we find the equations of the altitude lines to be ...

Altitude to B

  -7x -6y = -36 . . . . has a common factor of -1

  7x +6y = 36 . . . . .  in standard form

Altitude to C

  3x +6y = 48 . . . . has a common factor of 3

  x +2y = 16 . . . . . . . in standard form

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Additional comment

Standard form requires the leading coefficient be positive, and all the coefficients be mutually prime.

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Ver imagen sqdancefan