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Determine the frequency and energy for light with a wavelength of 699.8 nm .
=
s−1
=
kJ/mol
What is the color of light with a wavelength of 699.8 nm ? Refer to the electromagnetic spectrum as needed.


Determine the wavelength and energy for light with a frequency of 5.828×1014 s−1 .
=
nm
=
kJ/mol
What is the color of light with a frequency of 5.828×1014 s−1 ? Refer to the electromagnetic spectrum as needed.


Determine the frequency and energy for yellow light with a wavelength of 590.9 nm .
=
s−1
=
kJ/mol
Determine the wavelength and frequency for light with energy of 252.8 kJ/mol .

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The frequency is obtained from the Plank equation E = hf or E = hc/λ. The color of the light can be seen be examining the chart of the visible spectrum.

1) The given wavelength is 699.8 nm

Recall that;

f = c/λ

c = 3 × 10^8 m/s

f =  3 × 10^8/699.8 × 10^-9

f =4.29 × 10^14 s−1

E = hf/6.02 × 10^23

f = 6.6 × 10^-34 Js

E = 6.6 × 10^-34 × 4.29 × 10^14/6.02 × 10^23 × 1000

E = 4.7 × 10^-40 kJ/mol

The wavelength of 699.8 nm corresponds to red light.

2) Given that;

f = c/λ

λ = c/f

λ = 3 × 10^8/5.828 × 10^14 s−1

λ = 510 nm

This wavelength corresponds to blue light

3) For yellow light; wavelength = 590.9 nm or 590.9 × 10^-9

f = c/λ

f = 3 × 10^8/590.9 × 10^-9

f = 5.08 × 10^14 s−1

E = hf

E = 6.6 × 10^-34 × 5.08 × 10^14 s−1

E = 3.35 × 10^-19 J/6.02 × 10^23 × 1000 = 5.6 × 10^-40 kJ/mol

4) Energy = 252.8 × 10^3/6.02 × 10^23

Energy = 4.199 × 10^-19 J

E = hc/λ

λ = hc/E

λ = 6.6  × 10^-34 × 3 × 10^8/4.199 × 10^-19

λ = 4.72  × 10^-7 or 472 nm

f = c/λ

f =  3 × 10^8/4.72  × 10^-7

f= 6.4 × 10^14 s−1

Learn more; https://brainly.com/question/7143261