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If an individual proton has mass 1.007825 amu and an individual neutron has mass 1.008665 amu, and the observed atomic mass of gadolinium-157 is 156.92396 amu, what's its mass defect?
Question options:

A)

–1.38269 amu

B)

–1.35833 amu

C)

1.35833 amu

D)

1.38269 amu

Respuesta :

Answer: 1.38269

Explanation:

Answer:

–1.38269 amu

Explanation:

There are 64 protons and 93 Neutrons in gadolinium-157

If you multiply the number of protons and neutrons by their individual mass

P= 1.007825 amu * 64 = 64.5008

N= 1.008665 amu * 93 = 93.805845

Then add them together to get 158.306645 as the calculated mass.

Now, Subtract the calculated mass from the observed atomic mass

Δm = 156.92396 amu – 158.306645 amu

Δm = –1.38269 amu is your mass defect

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