Respuesta :

mhanifa

Answer:

  • [tex]-ab^2/189[/tex]

Step-by-step explanation:

See the steps below:

  • [tex]-ab^2/14 + ab^2/21+ab^2/18-ab^2/27=[/tex]
  • [tex]ab^2(-1/14+1/21+1/18-1/27)[/tex]

Find the LCM of 14, 21, 18 and 27:

  • 14 = 2*7
  • 21 = 3*7
  • 18 = 2*3*3
  • 27 = 3*3*3
  • LCM(14,21,18,27) = 2*7*3*3*3 = 378

Solve the fractions:

  • [tex]-1/14 + 1/21 +1/18-1/27=\\[/tex]
  • [tex]1/378(-27+18+21-14)=[/tex]
  • [tex]1/378(-2)=[/tex]
  • [tex]-1/189[/tex]

The answer is:

  • [tex]-ab^2/189[/tex]

[tex]\\ \sf\longmapsto \dfrac{-ab^2}{14}+\dfrac{ab^2}{21}+\dfrac{ab^2}{18}-\dfrac{ab^2}{27}[/tex]

  • Taking LCM

[tex]\\ \sf\longmapsto \dfrac{-27ab^2+18b^2+21ab^2-14ab^2}{378}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-2ab^2}{378}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-ab^2}{189}[/tex]

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