We have that the maximum height reached by the basketball from its release point is
[tex]S=1.3m[/tex]
From the question we are told
Generally the Newtons equation for Motion is mathematically given as
[tex]V^2=u^2+2as\\\\Therefore\\\\0=25-19.6*S\\\\S=\frac{25}{19.6}\\\\S=1.276[/tex]
[tex]S=1.3m[/tex]
Therefore
The maximum height reached by the basketball from its release point is
[tex]S=1.3m[/tex]
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