This given problem asks for the y-intercept of the linear equation.
The first step we need to is to transform the original equation into its slope-intercept form, y = mx + b (where m = slope, and b = y-intercept).
3x = 5y - 6
Subtract 3x on both sides:
3x - 5y - 3x = - 3x - 6
-5y = - 3x - 6
Divide both sides by -5:
-5y/-5 = (- 3x - 6) / -5
y = 3/5x + 6/5 (This is the slope-intercept form).
To solve for the y-intercept of the line, we must set x = 0 (because the y-intercept is the value of y when x = 0). The coordinate of the y-intercept is (0, b).
y = 3/5x + 6/5
y = 3/5(0) + 6/5
y = 0 + 6/5
y = 6/5
Therefore, the y-coordinate of the point where ‘L’ cuts the y-axis is 6/5.
