The horizontal distance traveled by the projectile is 7 m.
The given parameters;
height of the projection, h = 5 m
initial horizontal velocity of the projectile, v = 7 m/s
The time of flight of the projectile is calculated as;
[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\5 = 0 + 0.5\times 9.8t^2\\\\5 = 4.9t^2\\\\t^2 = \frac{5}{4.9} \\\\t^2 = 1.02\\\\t = \sqrt{1.02} \\\\t = 1 \ s[/tex]
The horizontal distance traveled by the projectile is calculated as;
X = vt
X = 7 x 1
X = 7 m
Thus, the horizontal distance traveled by the projectile is 7 m.
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