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show whether the following questions are dimensionally correct or not:
v^2=vt+2as​

Respuesta :

Answer:

v^2 = v t + 2 a s

(cm / sec)^2 = cm / sec * sec + 2 cm / sec^2 * cm

We know 2 a s = vf^2 - vi^2     (dim cm^2 / sec^2)

obviously v t has dim of cm and does not belong in the formula

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