coolkiddo30
contestada

Now how far did the 10 kg object fall during this 5 s? Remember: x_f=x_i+v_it+.5at^2x
f
​
=x
i
​
+v
i
​
t+.5at
2
and if unless specified xi =0 m, vi= 0 m/s and a= 9.81 m/s2



122.6 m


1226 m


50 m


59.81 m

Respuesta :

hamzaahmeds

This question can be solved using the equations of motion.

The object fell "122.6 m".

The distance fell by the object can be found by using the second equation of motion:

[tex]h = v_it+\frac{1}{2}gt^2[/tex]

where,

h =  distance fell = ?

vi = initial speed = 0 m/s

t = time interval = 5 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]h = (0\ m/s)(5\ s)+\frac{1}{2}(9.81\ m/s^2)(5\ s)^2[/tex]

h = 122.6 m

Learn more about equations of motion here:  

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

Ver imagen hamzaahmeds

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