Answer:
[tex]\displaystyle 2y^2(x + y) = 300[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle 2y^2(x + y) \\ x = 1 \\ y = 5[/tex]
Step 2: Evaluate
- Substitute in variables [Equation]: [tex]\displaystyle \displaystyle 2y^2(x + y) = 2(5)^2(1 + 5)[/tex]
- Exponents: [tex]\displaystyle \displaystyle 2y^2(x + y) = 2(25)(1 + 5)[/tex]
- (Parenthesis) Add: [tex]\displaystyle \displaystyle 2y^2(x + y) = 2(25)(6)[/tex]
- Multiply: [tex]\displaystyle 2y^2(x + y) = 300[/tex]