The temperature of a pot of water was 180.3°F and it cooled at a rate of -2.5°F for a minute after 20 minutes what was the temperature

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25-09-2021
Mathematics

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The temperature of a pot of water was 180.3°F and it cooled at a rate of -2.5°F for a minute after 20 minutes what was the temperature

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cooter1218 cooter1218 · Answer 1 · 2021-09-25T01:03:06+02:00

cooter1218 cooter1218

25-09-2021

Temperature after 20 minutes is found by multiplying-2.5 by 20 since it goes down by 2.5 degrees for one minute. -2.5 * 20 = -50. Adding this to 180.3 will give the temperature 130.3 degrees.

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