[tex]\frac{-8 \frac{+}{-} \sqrt{64-20} }{10}[/tex]Answer:
A -> H -> B -> E -> F
Step-by-step explanation:
Equation for Quadratic Formula:
[tex]\frac{-b \frac{+}{-} \sqrt{b^2-4ac} }{2a}[/tex]
a = 5, b = 8, c = 1
The following is letter A
[tex]\frac{-8 \frac{+}{-} \sqrt{8^2-4(5)(1)} }{2(5)}[/tex]
Next: Do basic arithmetic on the values
8^2 - 4(5)(1) = 64 - 20
2(5) = 10
Letter H ->
[tex]\frac{-8 \frac{+}{-} \sqrt{64-20} }{10}[/tex]
Next: Subtract 64-20 in the square root of the numerator
Letter B ->
[tex]\frac{-8 \frac{+}{-} \sqrt{44} }{10}[/tex]
Next: We see that [tex]\sqrt{44}[/tex] = [tex]\sqrt{(4)(11)} = 2\sqrt{11}[/tex]
Letter E ->
[tex]\frac{-8 \frac{+}{-} 2\sqrt{11} }{10}[/tex]
Lastly, multiply the top and bottom by 1/2
Letter F ->
[tex]\frac{-4 \frac{+}{-} \sqrt{11} }{5}[/tex]
