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A solution of citric acid (H₃C₆H₅O₇) with a known concentration of 0.200 M H₃C₆H₅O₇ is titrated with a 0.750 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 25.0 mL H₃C₆H₅O₇ , according to the following balanced chemical equation: H₃C₆H₅O₇ + 3 NaOH → Na₃C₆H₅O₇ + 3 H₂O

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ajinems

The quantity of NaOH required to reach the third equivalence point is 20mL.

Using the titration formula,

CaVa/CbVb = Na/Nb

Where,

Ca = concentration of citric acid (0.200 M)

Cb = concentration of NaOH (0.750 M)

Va = Volume of citric acid (25.0 mL)

Vb = volume of NaOH (x mL)

Na = number of reacting mole of citric acid (3)

Nb = number of reacting mole of NaOH (1)

Therefore Vb ( x mL) =CaVaNb/CbNa

                                 

 = 0.2× 25×3/0.75 ×1

                                   

= 15/0.75

                   Vb ( x mL) = 20 mL

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