Answer:
x=1
y=1
z= -3
Step-by-step explanation:
Start by solving for a variable and substituting into the other two
for example, (from the first equation) z= 3x+2y-8
substitute this for z into the other two equations to get
6x+7y= 13
13x+5y= 18
Now solve for x and y through elimination
mulitply the first equation by 5 and the second by 7
5(6x+7y)= 30x+35y = 65
7(13x+5y)= 91x+35y = 126
subtract them
(30x+35y)-(91x+35y)= 65-126
-61x= -61
x=1
Subsitute this into the equation
6(1)+7y= 13
7y=7
y=1
Now substiute these into the original equation
3(1)+2(1)-z=8
3+2-z=8
-z= 3
z= -3
