`solve the equation if there is no solution write no solution

Hii :))
[tex] \tt \: 4 | x + \frac { 1 } { 3 } | = 20 \\ \tt \: |x+\frac{1}{3}|=20 \div 4 \\ \tt \: |x+\frac{1}{3}|=5 \\ \tt \: \\ \\ \\ \tt \: x+\frac{1}{3}=5 \\ \tt \: x+\frac{1}{3}=-5 \\ \\ \\ \ \tt \: x =5 - \frac{1}{3} \\ \tt \: x = - 5 - \frac{1}{3} \\ \\ \\ \boxed{ \tt \: x=\frac{14}{3} \approx \: 4.66} \\ \boxed{\tt \: x=-\frac{16}{3} \approx \: - 5.33 }[/tex]
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[tex]\overbrace{ \underbrace{ \sf \: \infty \: Carry \: on \: Learning \: \infty }}[/tex]
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