2^-3 x 3^-2 as a fraction is 1/72 and (-2)^-3 x (-3)^-2 as a fraction is -1/72
How to solve the expression?
The expression is given as:
2^-3 x 3^-2
Apply the law of indices
[tex]\frac{1}{2^3} * \frac{1}{3^2}[/tex]
Evaluate the exponents
[tex]\frac{1}{8} * \frac{1}{9}[/tex]
Evaluate the product
[tex]\frac{1}{72}[/tex]
Also, we have:
(-2)^-3 x (-3)^-2
Apply the law of indices
[tex]\frac{1}{-2^3} * \frac{1}{-3^2}[/tex]
Evaluate the exponents
[tex]-\frac{1}{8} * \frac{1}{9}[/tex]
Evaluate the product
[tex]-\frac{1}{72}[/tex]
Hence, 2^-3 x 3^-2 as a fraction is 1/72 and (-2)^-3 x (-3)^-2 as a fraction is -1/72
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