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If at first the water in the fruit was 25% and after a few days it became 20% , How many Percent less did the mass of fruit become?

Respuesta :

Answer: [tex]0.2[/tex] or

5%

Step-by-step explanation:

Try to avoid this mistake

At first, the water in the fruit was 25%, then it dropped to 20%. That means we just have to find the difference between 25% and 20%.

Subtract 20 from 25

[tex]20 - 25\\\\5[/tex]

Therefore, we are left with 5%.

The mass of the fruit was 5% less. However, in some cases, it may be right, or wrong.

Here is the right solution

[tex]25\% - 20\%[/tex]

Since percentages are over 100, it will be simple to solve

[tex]\frac{25}{100} -\frac{20}{100}[/tex]

Simplify

[tex]\frac{25-20}{100}\\\\20-25=5\\\\\frac{5}{100}\\\\\frac{1}{20}[/tex]

[tex]\frac{1}{20}=5\%[/tex]

The mass of the fruit became 5 percent less.

  • Initial percent=25\%
  • Final percent=20\%

Now

[tex]\\ \bull\tt\looparrowright \Delta \%=Initial\:percent-Final\:Percent[/tex]

[tex]\\ \bull\tt\looparrowright \Delta \%=25-20[/tex]

[tex]\\ \bull\tt\looparrowright \Delta \%=5\%[/tex]