Respuesta :

Answer:

y = - 2x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (2, - 3) ← 2 ordered pairs from the table

m = [tex]\frac{-3-(-1)}{2-1}[/tex] = [tex]\frac{-3+1}{1}[/tex] = - 2 , then

y = - 2x + c ← is the partial equation

To find c substitute any ordered pair from the table into the partial equation

Using (3, - 5 ) , then

- 5 = - 6 + c ⇒ c = - 5 + 6 = 1

y = - 2x + 1 ← equation of line

charlief22

Answer:

Step-by-step explanation:

We will need to find the equation and put it in the form y = mx + b where m is the slope and b is the y intercept.

Step 1 - Calculate the slope via the slope formula:

[tex]\frac{(y2 - y1)}{(x2 - x1}[/tex]

We will use the first two x and y variables in the table, so simply plug the values in.

[tex]\frac{(-3) - (-1)}{2 - 1}\\[/tex]

= [tex]\frac{-2}{1} = -2[/tex]

This means the slope is 2 (y = -2x + b).

Step 2 - Plug the variables in:

To calculate the b, we can use one of the pairs of coordinates i.e. (1, -1) to calculate b by putting the variables into the above equation:

y = -2x + b

-1 = -2(1) + b

-1 = -2 + b

-1 + 2 = b

b = 1

This means the equation is:

y = -2x + 1

Hope this helps!

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