Annyohasayo Annyohasayo

25-09-2021
Mathematics

contestada

please solve this......
[tex] \frac{ {c}^{2} + 2cd - {15d}^{2} }{ {4c}^{2} + 20cd } [/tex]

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ghaithgh ghaithgh

25-09-2021

Answer:

[tex] \frac{ {c}^{2} + 2cd - 15 {d}^{2} }{4 {c}^{2} + 20cd} = \frac{(c - 3d)(c + 5d)}{4c(c + 5d) } \\ \\ \\ = \frac{c - 3d}{4c} [/tex]

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