Would the product of two irrational elements always be irrational? Please justify or explain your response

Respuesta :

Answer:

No

Step-by-step explanation:

Simple counterexample: [tex]\sqrt{2}[/tex] which is famously irrational. As the second number let’s take [tex]2\sqrt{2}[/tex] which obviously is also irrational. Their product is [tex]\sqrt{2}\cdot 2\sqrt{2} = 2\cdot 2 = 4[/tex] which is a rational number.