The object's velocity is purely horizontal at the time "2 s".
This question can be solved using the given equations of x and y coordinates of the velocity.
At the time, when the velocity of the object is purely horizontal, the y-coordinate of the velocity must be equal to zero. Therefore, by setting the y-coordinate of the velocity to zero, we can find out the time at which the velocity of the object is purely horizontal.
[tex]v_y(t)=2t^2-8 = 0\\2t^2 = 8\\t^2 = 4\\[/tex]
t = 2 s
Learn more about velocity components here:
https://brainly.com/question/3368?referrer=searchResults
The attached picture shows velocity components.