audreyburkett12
contestada

8. Write the equation of a line that is perpendicular to the given line and that passes through the
given point.
y – 3 = 8/3(x + 2); (–2, 3)
(1 point)
A.y + 3 = -3/8 (x – 2)
B.y – 3 = –3/8 (x + 2)
C.y – 2 = –3/8 (x + 3)
D.y + 3 =3/8 (x – 2)


Please help, i have no idea where to even start

Respuesta :

texaschic101
y - 3 = 8/3(x + 2)...the slope here is 8/3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will have a slope of -3/8

y - y1 = m(x - x1)
slope(m) = -3/8
(-2,3)....x1 = -2 and y1 = 3
now we sub
y - 3 = - 3/8(x - (-2)...not done yet
y - 3 = -3/8(x + 2) <===

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