meerkat18
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Find the perimeter of the following shape, rounded to the nearest tenth:

Shape ABCD is shown. Point A is at 5, 5. Point B is at 7, 3. Point C is at 3, 0. Point D is at 1, 2.

12.5
15.7
16
16.5

Find the perimeter of the following shape rounded to the nearest tenth Shape ABCD is shown Point A is at 5 5 Point B is at 7 3 Point C is at 3 0 Point D is at 1 class=

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nobillionaireNobley
Perimeter of the shape is 2(AB) + 2(BC)

AB = sqrt((7 - 5)^2 + (3 - 5)^2) = sqrt(2^2 + (-2)^2) = sqrt(4 + 4) = sqrt(8) = 2.83
BC = sqrt((3 - 7)^2 + (0 - 3)^2) = sqrt((-4)^2 + (-3)^2) = sqrt(16 + 9) = sqrt(25) = 5

Perimeter = 2(AB) + 2(BC) = 2(2.83) + 2(5) = 5.66 + 10 = 15.7

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