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If radius BE is a perpendicular bisector of chord AC , BD = 7 cm, and CD = 9 cm, then what is AB to the nearest tenth?

(Points : 1)
10.2 cm

10.9 cm

11.4 cm

11.8 cm

If radius BE is a perpendicular bisector of chord AC BD 7 cm and CD 9 cm then what is AB to the nearest tenth Points 1 102 cm 109 cm 114 cm 118 cm class=

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MissPhiladelphia
Thank you for posting your question here at brainly. Feel free to ask more questions. 

The best and most correct answer among the choices provided by the question is 11.4 cm .


Hope my answer would be a great help for you.  

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